Đề thi thử THPT QG môn Toán - Mã đề thi 138

ri rru rstl rHPT QUoc cIA LAN I

Ndm hsc 2016-2017; Mdn: Todn

Thdi gian tdm bdi 90 phtit, khong ke thdi gian giao d€

Hg va ten thi sinh:......... ........ Phong thi: SBD:

Ciu l: Hdm s6 y = 3.rr + 2 dong bit5n tr€n khoang nAo sau ddy?

so GrAo DUC VA DAO TAO TiNTJ BA zuA Wn rc rAU

DE CHINH TITUC .^) ) ^, (E€ g6m 06 trang)

Me d6 138

Ciu 2z Gi6 tri cuc ti6ti yr., gitahdm s6 ! = x3 - 3x2 + 1 ld

A. yr., =7. B. lcr--3. C,yrr=0. D. yr, =2.

Ciu 3: Cho hdm sO y = /(x) lien tuc tr€n l-t;:] vd c6 bdng bi6n thi€n

Khing dinh ndo sau ddy ld khing dinh dring?

A. Gi6 tri nho nhAt cua hdm sO tr6n [-t;:] bing -2.

B. Gie tri nho nh6t cira hdm so tren [-i;3] bing -i.

C. Gi6 tri lon nhAt cua hdm so tr6n [-1;3] bing :.

D. Gi6 tri nho nhAt cira ham s6 tr€n [-1;3] bang 2.

Cf,u 4: Eo thihdm sd y =+ co ducrng tiqm cin ngang ldr x+l A.y=-I. B.y=2. C,x=-1. D.x=2.

ciu5: 56 giao di6m cuaduorrg thing (a)ty:x*1 vddrrongcong y=xr+l ld A.0. B. 1. c.2. D.3.

Ciu 6: Goi M, m I|,nluort ld gitttrllo'n rilr6t vd gia tri nh6 nhit cua ham sd -f (r) = xtl2lnx-3) trOn doan

f. r-l ,,,J | 1; e' l. Khdng dinh ndo sau ddy dring?

A.(0,+*) . e. [--,-?') \ 3) c. ( -?,**') . \' 3' ) D. (-..o;0).

D. M +m=-3-e2 A. M+n't=eo -3. B. M+n1=eo -e'. C. M+m=eo.

Cdu 7: Duong cong 6 hinh b6n (Hinh 1) le do thi cua

mQt hdm sd trong bdn hdm sO duoc liqt kd trong bon

phuong 6n A, B, C, D du6i dAy. H6i d6 Id hdm sd ndo ?

L. y=-x' +3x+2. B. ! = x3 +3x+2'

C,y=x3 -3x+2. D. y=-x3 -3x+2.

( Flinb 1)

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cAu 8: tAt ca cfrc gtittri cua tham s0 rr d€ ham sd y = x' - mxt + 3'r + i ddng bi6n tron R' ld

A. -3 <m<3. B. -2<rn<2. C. m>3. D. m<-3.

Ciu 9: Cho ham s6 y = /(r) co dao ham cAp hai tren (a: b) vd xo e(a;b) . Kh*g dfnh nao sau day lii

rr.l Knang olnn oung r

. ,,i -,/ \ n , .t't \ ^ A. NCu .f '(ro)= 0 uu /"(.to)> 0 thi "ro lir di6m cuc rieu cua hirm s6.

B. Neu ham so dat cuc tieu tai diem -ro thi /'(.ro)= O vd. f ' (.to)t O.

^ --.4 -,/ , ^,,/ \ ^ C.Neu .f,(to)=0 uu /"(_.0)<0 thi _ro iirdi€mcuctieucuahdms6.

D.Ndu xo ld.di€mcuctri ctahdms6thi f'(*o)=0 va f"(ro)*0.

Ciu 10: Gi6 tri cira bi6u thuc A = 3J1-t .9u5 .,7'-tr bane c" 27. D. 81. 116s th6a mdn aa < as ; iogr -1< logr: . Khdng dinh ndo sau dAy )4

A'.3. 8.9.

Ciu 11: Cho a, b ld hai sd thuc ducrng khdc 1

ld ttfng? A. a >l;b >1.

Cflu 12: Cho 1og, * =L

3 A- n. -.4

Ciu 13: Bi0u thuc O =

5 A' Q=oi '

CAu 14: Cho log, 3: a,

4.. 6a + 4b.

^3 u A. l/ -- 4

'7 C' Q=n1 '

logu 67 5 theo a vd b lit

c. n+1u. 2

D. a>l;O<b <1.

A D.- 1a 1J

3 D. -a+b. I

B. 0< a<1;b>1. C. 0<a<\A<b<I.

. Khi d6 gi6 tri bi6u rhuc o = to*'it":)-tot' ; oin, x-+1og6x s-l 4

1) r 11 IJ

8 D' a= n'

(r)' y=l-l \a)

^n- r1 f/ \,, y =- A+

oo .1,[7 Qoi a > 0; a + 1). Ding thu'c ndro sau ddy thing? : B'Q=at '

, ^.1 1.: logr ) :0. IJleu Olen

B.4a+6b.

Cf,u 15: Cho a > 0,a + 1 . M€nh dO ndo sau dAy thing? :" A. HAm s6 y: a'' vai a > 1 nghich bi€n trdn tdp R .

B. Hdm s6 y = a' voi 0 < a <1 d6ng bi6n trdn t4p R .

^ ^^... A , (t).. ^ J C. D0 thi hai hdm so | = a';y =l - | ludn nam phia tr€n truc hodnh. - \a )

D. EO thi hdm s6 y: a' nim phia tr6n truc hodnh vd d6 thi hdm s6

hodnh.

nim phia du6i tryc

Ciu 16: Cho hinh chop S.lB C co ddy lir tam gi6c dAu canh bing a , canh bdn Sl r.'udng g6c vdi mp(ABC)

vd Sl = oJ3. th6 tich cua kh6i chop S.ABC lit

B.V=a3 D.V=

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